Given a peak voltage of 340VAC, what is the approximate effective voltage?

Given a peak voltage of 340VAC, what is the approximate effective voltage?

• A. 240V
• B. 340V
• C. 480V
• D. 960V

Answer: (A)

To determine the approximate effective voltage from a given peak voltage in an AC circuit, it's important to understand the relationship between peak voltage and effective (or root mean square, RMS) voltage. The effective voltage is derived from the peak voltage by using a conversion factor that accounts for the shape of the AC waveform, which is typically sinusoidal. For a sinusoidal waveform, the relationship is defined as: Effective Voltage (Vrms) = Peak Voltage (Vpeak) / √2 Given a peak voltage of 340VAC, you can calculate the effective voltage as follows: Vrms = 340V / √2 ≈ 340V / 1.414 ≈ 240V This shows that the approximate effective voltage for a peak voltage of 340VAC is indeed around 240V. This conversion is fundamental in alternating current (AC) systems as it provides a voltage value that can be effectively used for calculations involving power, current, and load. Therefore, in this context, the choice indicating 240V as the effective voltage correctly represents the calculated conversion from the peak voltage.

To determine the approximate effective voltage from a given peak voltage in an AC circuit, it's important to understand the relationship between peak voltage and effective (or root mean square, RMS) voltage. The effective voltage is derived from the peak voltage by using a conversion factor that accounts for the shape of the AC waveform, which is typically sinusoidal.

For a sinusoidal waveform, the relationship is defined as:

Effective Voltage (Vrms) = Peak Voltage (Vpeak) / √2

Given a peak voltage of 340VAC, you can calculate the effective voltage as follows:

Vrms = 340V / √2 ≈ 340V / 1.414 ≈ 240V

This shows that the approximate effective voltage for a peak voltage of 340VAC is indeed around 240V. This conversion is fundamental in alternating current (AC) systems as it provides a voltage value that can be effectively used for calculations involving power, current, and load.

Therefore, in this context, the choice indicating 240V as the effective voltage correctly represents the calculated conversion from the peak voltage.