A transformer has 200 windings on its primary which received 120VAC. What is the voltage across the secondary with 400 windings?

A transformer has 200 windings on its primary which received 120VAC. What is the voltage across the secondary with 400 windings?

• A. 60V
• B. 120V
• C. 240V
• D. 400V

Answer: (C)

To find the voltage across the secondary winding of a transformer, you can use the transformer equation, which relates the primary and secondary voltages to their respective number of windings. The formula is \[ \frac{V_p}{V_s} = \frac{N_p}{N_s} \] where \(V_p\) is the primary voltage, \(V_s\) is the secondary voltage, \(N_p\) is the number of turns (or windings) on the primary side, and \(N_s\) is the number of turns on the secondary side. In this case, the primary winding count \(N_p\) is 200, and the secondary winding count \(N_s\) is 400. The primary voltage \(V_p\) is given as 120VAC. Using the transformer equation: 1. Substitute the known values into the formula: \[ \frac{120V}{V_s} = \frac{200}{400} \] 2. Simplifying the ratio of windings: \[ \frac{200}{400} = 0.5 \] 3. This means: \[ \frac{120V}{V_s} = 0.5

To find the voltage across the secondary winding of a transformer, you can use the transformer equation, which relates the primary and secondary voltages to their respective number of windings. The formula is

[

\frac{V_p}{V_s} = \frac{N_p}{N_s}

]

where (V_p) is the primary voltage, (V_s) is the secondary voltage, (N_p) is the number of turns (or windings) on the primary side, and (N_s) is the number of turns on the secondary side.

In this case, the primary winding count (N_p) is 200, and the secondary winding count (N_s) is 400. The primary voltage (V_p) is given as 120VAC.

Using the transformer equation:

1. Substitute the known values into the formula:

[

\frac{120V}{V_s} = \frac{200}{400}

]

2. Simplifying the ratio of windings:

[

\frac{200}{400} = 0.5

]

3. This means:

[

\frac{120V}{V_s} = 0.5